Let the two outer numbers be N1 and N2, and the middle number be M. We look for a pattern relating N1, N2, and M in the given examples: 1) 8 (97) 6: N1=8, N2=6, M=97. 2) 4 (56) 5: N1=4, N2=5, M=56. 3) 6 (75) 4: N1=6, N2=4, M=75. Let's test the pattern $M = (N1 \times 10 + N2) + K$: 1) $(8 \times 10 + 6) = 86$. $86 + K = 97 \implies K = 11$. 2) $(4 \times 10 + 5) = 45$. $45 + K = 56 \implies K = 11$. 3) $(6 \times 10 + 4) = 64$. $64 + K = 75 \implies K = 11$. The pattern seems to be $M = (N1 \times 10 + N2) + 11$. Applying this pattern to the last case: 7 (?) 8. N1=7, N2=8. M = $(7 \times 10 + 8) + 11 = 78 + 11 = 89$.