The extension of a tapering bar is related to the product of its end diameters, while the extension of a uniform bar is related to the square of its diameter. For equal extensions, the uniform diameter should be the geometric mean of the tapering end diameters.
A gradually varying cross-section tapering bar with diameter of the end sections being d1 and d2 and a bar having uniform cross section with diameter d have the same length L and subjected to the same axial pull P and are made of same material, then both the bars will have the same extension if d is equal to : - (5) Question not attempted
Asked in Assistant Eng. (Mechanical) Competitive Examination, 2023 · Topic: Mechanics (Elasticity (Stress, Strain, Hooke's Law, Elastic Moduli))
More Physics questions
- A simply supported beam of constant flexural rigidity and length 2L carries a concentrated load P at its mid span and the maximum deflection under the load is δ. A cantilever beam of the same flexural rigidity and length L is subjected to load P at its free end. Determine the relation between the deflection at free end of the cantilever with δ. - (5) Question not attempted
- A steel member of area of cross section 1000 mm², having a length of 1 m is subjected to an axial compressive load of 10 kN. Assuming the case of pure compression in the member, the axial deflection is given by: (Take E = 200 GPa) - Question not attempted
- The S-N curve for steel becomes asymptotic nearly at - Question not attempted
- The life of a ball bearing at a load of 10 kN is 8000 hours. Its life in hours, if the load is increased to 20 kN, keeping all other conditions same, is : - Question not attempted
- A bolted joint is so designed that the stiffness of a threaded portion (K₁) is equal to the stiffness of unthreaded portion (K₂) of the bolt in a clamped region, then combined stiffness (effective) (Kₑ) of the bolt is given by - Question not attempted
- Complex potential is defined as - $\phi + i\psi$ - $\phi - i\psi$ - $\psi + i\phi$ - $\psi - i\phi$
- A Propped cantilever beam is loaded with uniformly distributed load on whole span such that that deflection at prop end of the beam is zero. The reaction of the prop end of the beam is calculated by (Take usual notations for all quantities). - (1) $\frac{3}{8} wl$ - (2) $\frac{7} {8} wl$ - (3) $\frac{5}{8} wl$ - (4) $\frac{5}{7} wl$
- A two span continuous beam is simply supported by three supports A, B and C from left to right respectively and subjected to U.D.L. of w kN/m throughout the span. Then negative moment will be generated at