Formulas for velocity and acceleration in SHM are $|v| = \omega \sqrt{A^2 - x^2}$ and $|a| = \omega^2 |x|$. The time period is $T = 2\pi/ \omega$.
A particle executes linear simple harmonic motion with amplitude of 2 cm. When the particle is at 1 cm from the mean position, the magnitudes of the velocity and the acceleration are equal. Then its time period (in seconds) is:
Asked in UPSC NDA 2 2016 · Topic: Mechanics (Simple Harmonic Motion and Damped/Forced Oscillations)
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