Train 1 leaves Delhi at 9 a.m. at 25 km/hr. Train 2 leaves Delhi at 2 p.m. at 35 km/hr. Train 2 leaves 5 hours after Train 1 (2 p.m. - 9 a.m. = 5 hours). In these 5 hours, Train 1 covers a distance = Speed Time = 25 km/hr 5 hrs = 125 km. So, at 2 p.m., Train 1 is 125 km ahead of Delhi, and Train 2 is at Delhi (0 km from Delhi). Train 2 is faster than Train 1, so it will eventually catch up. Let T be the time in hours after 2 p.m. when Train 2 catches up with Train 1. Distance covered by Train 1 from Delhi in T hours after 2 p.m. = Initial head start + Distance covered in T hours = 125 km + 25 km/hr T hrs. Distance covered by Train 2 from Delhi in T hours after 2 p.m. = Speed Time = 35 km/hr T hrs. When they meet, their distances from Delhi are equal: 125 + 25T = 35T 125 = 35T - 25T 125 = 10T T = 125 / The meeting distance from Delhi is the distance covered by Train 2 in 12.5 hours: Distance = Speed (Alternatively, check distance covered by Train 1: km)
A train travelling at 25 km/hr. leaves Delhi at 9 a.m. and another train leaves Delhi at 35 km/hr. at 2 p.m. in the same direction. At how many kms from Delhi do they meet ?
Asked in HAS Prelims 2023 · Topic: Mechanics (Newton's Laws of Motion and their applications)
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