In the reaction $\text{CuO} + \text{H}_2 \xrightarrow{\Delta} \text{Cu} + \text{H}_2\text{O}$: - Copper in CuO has an oxidation state of +2, and in Cu, it is 0. Thus, copper is reduced (gain of electrons/decrease in oxidation state). - Hydrogen in H₂ has an oxidation state of 0, and in H₂O, it is +1. Thus, hydrogen is oxidized (loss of electrons/ increase in oxidation state). This is a redox reaction.