A relation is in BCNF if for every functional dependency X → Y, X is a superkey. In this case, with FDs A → B, B → C, and C → D, and {A} as the primary key (and thus the only candidate key and superkey), the dependencies B → C and C → D violate the BCNF condition because neither B nor C are superkeys. Therefore, the relation is not in BCNF.