These are simple saturated hydrocarbons (alkanes) with the general formula CnH2n+2. The molecular formulas are: A. Methane: CH4 (n=1) B. Ethane: C2H6 (n=2) C. Propane: C3H8 (n=3) D. Butane: C4H10 (n=4) E. Pentane: C5H12 (n=5) The atomic weight of Carbon (C) is approximately 12.01 g/mol, and Hydrogen (H) is approximately 1.008 g/mol. The molecular weights are: A. CH4: 1 12.01 + 4 molecular weight increases directly with the number of carbon atoms (and consequently, hydrogen atoms). Therefore, the order A (Methane)
Consider the following hydrocarbons : A. Methane B. Ethane C. Propane D. Butane E. Pentane What is the correct sequence of increasing order of their molecular weight ? Select the code for the correct answer from the options given below :
Asked in KPSC KAS Prelims 2015 · Topic: Hydrocarbons (Alkanes: Preparation, Physical and Chemical Properties)
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