The bond order of a diatomic molecule or ion can be calculated using its molecular orbital electronic configuration. Removing an electron from a bonding molecular orbital decreases bond order, while removing an electron from an antibonding molecular orbital increases bond order.
Consider the following transformations: (A) N$_{2}$ $\rightarrow$ N$_{2}^{+}$ (B) O$_{2}$ $\rightarrow$ O$_{2}^{+}$ Choose the most appropriate option related to above transformations - - (5) Question not attempted
Asked in Department Recruitment 2024 (Chemist) 2024 · Topic: Atomic Structure (Electronic Configurations of Multi-electron Atoms and Ions)
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Answer: D. In (A) bond order decrease while in (B) bond order decrease.
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