- Average acceleration is defined as the change in velocity divided by the time interval. - From the given velocity-time graph, the velocity at t = 8 s is approximately 10 m/s. - From the graph, the velocity at t = 12 s is approximately 6 m/s. - The time interval is Δt = 12 s - 8 s = 4 s. - The change in velocity is Δv = v(12s) - v(8s) = 6 m/s - 10 m/s = -4 m/s. - Average acceleration = Δv / Δt = (-4 m/s) / (4 s) = -1 m/s².
Consider the following velocity and time graph: Which one of the following is the value of average acceleration from 8 s to 12 s?
Asked in UPSC NDA 2 2018 · Topic: Mechanics (Newton's Laws of Motion and their applications)
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