The torque ($\vec{\tau}$) of a force ($\vec{F}$) about a point (taken as the origin in this case) is calculated as the cross product of the position vector ($\vec{r}$) from the point to the point of application of the force and the force vector itself: $ \vec{\tau} = \vec{r} \times \vec{F}$. The calculation is performed using the determinant method for vector cross products.
Find the torque of a force $\vec{F} = 7\hat{i} + 3\hat{j} - 5\hat{k}$ about the origin. The force acts on a particle whose position vector is $\vec{r} = \hat{i} - \hat{j} + \hat{k}$.
Asked in Co operative Supervisor & Environment Supervisor (Group C) Exam 2023 · Topic: Mechanics (Rigid Body Dynamics (Euler Angles, Tops and Gyroscopes))
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