We can rewrite the equation as 2ᵃ⁻³ = 64¹². To solve for 'a', we need to express both sides of the equation with the same base. The base on the left side is 2. We can express 64 as a power of 2. 64 = 2 × 2 × 2 × 2 × 2 × 2 = 2⁶.
If 2ᵃ⁻³ – 64¹² = 0, what is the value of a ?
Asked in GPSC Prelims CSP 1 2017 · Topic: Measurement/Unit (Unit Conversion Techniques)
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