If the distance (r) is doubled (2r), the new force (F') would be F' = G (m1 m2) / (2r)² = G (m1 m2) / (4r²) = (1/4) [G (m1 m2) / r²] = (1/4) F. Therefore, the gravitational force would be one fourth of its original value.
If the distance between the Earth and the Sun were twice what it is now, the gravitational force exerted on the Earth by the Sun would be
Asked in UPPSC Upper Mains 2009 · Topic: Mechanics (Gravitation and Central Force Motion (Kepler's Laws))
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