The velocity ratio of a belt drive with slip is calculated by considering the reduction in speed at each stage. If $N_1$ is the driver speed and $N_2$ is the follower speed, and $s_1$ and $s_2$ are the percentage slips at the driver and follower respectively, the velocity ratio $\frac{N_2}{N_1} = (1 - s_1/100)(1 - s_2/100)$ for equal diameter pulleys.
In a flat belt drive, the slip between the driver and belt is 1% and slip between the belt and follower is 3%. If the pulley diameters for the driver and follower are equal, the velocity ratio of the drive is: - (5) Question not attempted
Asked in Assistant Eng. (Mechanical) Competitive Examination, 2023 · Topic: Mechanics (Newton's Laws of Motion and their applications)
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