Lecturer and Coach (School Edu. Dept.) Comp. The work done by a force is calculated as W = F · d = |F||d|cosθ, where θ is the angle between the force and displacement vectors. - If the force is in the direction of displacement (θ = 0°), work done is positive. - If the force is opposite to the direction of displacement (θ = 180°), work done is negative. - If the force is perpendicular to the displacement (θ = 90°), work done is zero. The question requires mapping these conditions to the labels (A), (B), and (C) in Column I.
In each of the case in Column-I, a force F is acting on an object of mass m. The direction of displacement is from West to East shown by longer arrow. Match the Column-I and Column- II and choose correct option : Column-I Column-II (Force on an Object) (Work done by Force F) (A) (i) Positive (B) (ii) Negative (C) (iii) Zero Codes : (A) (B) (C) (1) (i) (ii) (iii) (2) (i) (iii) (ii) (3) (ii) (iii) (i) (4) (iii) (i) (ii) (5) Question not attempted
Asked in Exam 2024 Group d 2024 · Topic: Mechanics (Work, Energy, and Power)
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