- The car starts from O (0 km). It goes to C (60 km) and then comes back to B (35 km). - Distance is the total path length covered. The car travels from O to C (60 km) and then from C back to B (60 km - 35 km = 25 km). Total distance covered = 60 km + 25 km = 85 km. - Displacement is the straight-line distance and direction from the initial position to the final position. Initial position is O (0 km). Final position is B (35 km). The displacement is B - O = 35 km - 0 km = 35 km in the positive direction. The magnitude of displacement is 35 km.
The motion of a car along a straight path is shown by the following figure : [Figure shows a line starting from O (0km) and points A (25km), B (35km), C (60km) along the path] The car starts from O and reaches at A, B and C at different instants of time. During its motion from O to C and back to B, the distance covered and the magnitude of the displacement are, respectively
Asked in UPSC NDA 1 2016 · Topic: Mechanics (Newton's Laws of Motion and their applications)
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