Since the expression repeats, we can write: $x = 2 - \frac{1}{x}$ Multiply by x: $x^2 = 2x - 1$ Rearrange the equation: $x^2 - 2x + 1 = 0$ This is a perfect square trinomial: $(x - 1)^2 = 0$ Solving for x: $x - 1 = 0$ $x = 1$
The value of the continued fraction $2- \frac{1}{2-\frac{1}{2-\cdots}}$ is
Asked in BPSC Prelims Exam 67th Cancelled · Topic: Measurement/Unit (Physical Quantities (Fundamental and Derived))
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