Let the dimensions of the rectangular box be length (l), width (w), and height (h). The areas of the three adjacent faces are given as lw = 42 cm², wh = 30 cm², and hl = 35 cm². The volume (V) of the box is lwh. Multiply the three given area equations: (lw) (wh) (hl) = 42 30 35 l²w²h² = 44100 (lwh)² = 44100 V² = 44100 V = sqrt(44100) = sqrt(441 100) = sqrt(441) sqrt(100) = 21 10 = 210. The volume is 210 cm³.
The volume of a rectangular box whose area of three adjacent faces are 42 cm², 30 cm² and 35 cm² is ...........................
Asked in GPSC Prelims CSP 1 2018 · Topic: Mechanics (Newton's Laws of Motion and their applications)
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