The relationship between wave speed (v), frequency (f), and wavelength (λ) is given by v = fλ. Given frequency f = 3 × 10⁵ Hz. Speed of sound in air v_air = 300 m/s. Speed of sound in the medium v_medium = 10 × v_air = 10 × 300 m/s = 3000 m/s. We need to find the wavelength λ in the medium. Using the formula λ = v_medium / f: λ = 3000 m/s / (3 × 10⁵ Hz) = 3000 / 300000 m = 1/100 m = 0.01 m.
Ultrasonic waves of frequency 3 × 10⁵ Hz are passed through a medium where speed of sound is 10 times that in air (Speed of sound in air is 300 m/s). The wavelength of this wave in that medium will be of the order of
Asked in UPSC NDA 1 2015 · Topic: Sound (Ultrasound and Infrasound: Production, Properties, and Applications (SONAR, Medical, Industrial))
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