The road network forms a graph. To start from a city and return to it without traversing the same road twice means finding elementary cycles (circuits) that pass through the starting city. Let's label the cities A, B, C, D. The figure likely shows a complete graph K4, where every city is connected to every other city by a road. If it's K4: - From city A, you can go to B, C, or D (3 options). - If you go A -> B, you can then go B -> C or B -> D (2 options). - If you go A -> B -> C, you must go C -> D to visit all cities or C -> A to return directly. Since you must return to the start and not use the same road twice, you need to complete a cycle. - Cycles of length 3 involving A: A-B-C-A, A-C-B-A, A-B- D-A, A-D-B-A, A-C-D-A, A-D-C-A. (6 ways starting from A). - Cycles of length 4 involving A: A-B- C-D-A, A-B-D-C-A, A-C-B-D-A, A-C-D-B-A, A- D-B-C-A, A-D-C-B-A. (6 ways starting from A). Total ways starting from A and returning to A = 6 (length 3) + 6 (length 4) = 12. Since the graph is symmetric (a complete graph), the number of ways is the same regardless of the starting city.