The formula used is Q = mcΔT, where Q is the heat energy absorbed (20 kJ = 20,000 J), m is the mass, c is the specific heat capacity (400 J/(kg °C)), and ΔT is the change in temperature (25 °C - 15 °C = 10 °C). Rearranging the formula to find mass: m = Q / (cΔT). Plugging in the values: m = 20000 J / (400 J/(kg °C) 10 °C) = 20000 / 4000 kg = 5 kg.
What is the mass of a material, whose specific heat capacity is 400 J/(kg °C) for a rise in temperature from 15 °C to 25 °C, when heat received is 20 kJ?
Asked in UPSC NDA 1 2022 · Topic: Heat and Thermodynamics (Calorimetry and Phase Changes (Specific Heat, Latent Heat))
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