When a number is divisible by 7, it gives 3 as remainder. Find the total possible numbers of such type lying between 11 and

The correct answer is (a).

A number is divisible by 7 if the remainder when it is divided by 7 is 0. A number that gives 3 as a remainder when divided by 7 is 3 more than a multiple of 7. The first multiple of 7 after 11 is 14, so the first number that gives 3 as a remainder when divided by 7 is 14 + 3 = 17. The last multiple of 7 before 18 is 14, so the last number that gives 3 as a remainder when divided by 7 is 14 - 3 = 11. Therefore, there are 2 such numbers: 17 and 11.

(b) is incorrect because 12 is not divisible by 7. (c) is incorrect because 15 is divisible by 3, so it cannot give 3 as a remainder when divided by 7. (d) is incorrect because 18 is divisible by 2, so it cannot give 3 as a remainder when divided by 7.