To find the oxidation state of nitrogen in each compound, we use the rule that the sum of oxidation states in a neutral compound is zero, and oxygen typically has an oxidation state of -2 (except in peroxides or when bonded to fluorine). A) NO: N + (-2) = 0 => Oxidation state of N = +2 B) NO₂: N + 2(-2) = 0 => N - 4 = 0 => Oxidation state of N = +4 C) N₂O: 2N + (-2) = 0 => 2N = 2 => Oxidation state of N = +1 D) N₂O₅: 2N + 5(-2) = 0 => 2N - 10 = 0 => 2N = 10 => Oxidation state of N = +5 Comparing the oxidation states (+2, +4, +1, +5), the highest is +5 in N₂O₅.
Which one of the following nitrogen oxides has the highest oxidation state of nitrogen?
Asked in UPSC CDS 2 2018 · Topic: Sulphur, Nitrogen, Halogen, Inert Gases (Oxides of Nitrogen: Types, preparation, properties, structures, and environmental impact)
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