Newton's Second Law (F=ma) is fundamental in relating force, mass, and acceleration. Ensure consistent units (SI units like Newtons, kilograms, and meters per second squared).
A 5 N force is defined when a mass of 10 kg is accelerated with
Asked in UPSC NDA 1 2022 · Topic: Mechanics (Newton's Laws of Motion and their applications)
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- Two identical spring balances S₁ and S₂ are connected one after the other and are held vertically as shown in the figure. A mass of 10 kg is hanging from S₂. If the readings on S₁ and S₂ are W₁ and W₂ respectively, then:
- A particle is moving in a circle of radius R with a constant speed v. Its average acceleration over the time when it moves over half the circle is :
- Two forces of 5.0 N each are acting on a point mass. If the angle between the forces is 60°, then the net force acting on the point mass has magnitude close to :
- One block of 2·0 kg mass is placed on top of another block of 3·0 kg mass. The coefficient of static friction between the two blocks is 0·2. The bottom block is pulled with a horizontal force F such that both the blocks move together without slipping. Taking acceleration due to gravity as 10 m/s², the maximum value of the frictional force is :
- Which one of the following is an example of Second Class Lever ?
- A uniform meter scale of mass 0.24 kg is made of steel. It is kept on two wedges, W₁ and W₂, in a horizontal position. W₁ is at a distance of 0.2 m from one of its ends, while W₂ is at distance of 0.4 m from the other end. If the force on the scale is N₁ due to W₁ and N₂ due to W₂, then : (take g = 10.0 m s⁻²) Ans: C For a uniform meter scale of mass 0.24 kg, its of mass, which is at the 0.5 m mark from either end. W₁ is at 0.2 m from one end (say, the 0m mark), and W₂ is at 0.4 m from the other end (the 1m mark), For equilibrium, the sum of upward forces equals the sum of downward forces (N₁ + N₂ = W = 2.4 N), and the sum of torques about any point is zero. Taking torques about the point W₁ (at 0.2m), the weight W (at 0.5m) creates a clockwise torque W = N₂ 0.4 Nm. Setting the sum of torques to zero: N. Substituting N₂ into the force equation: N₁ + 1.8 330. Which one of the following about different frictional forces is correct?
- If the block P as shown in the figure below were to be at rest, what should the magnitude of force F be ?
- A block of mass 2 kg, moving with the initial speed of 3 m/s comes to rest on a rough horizontal surface after travelling a distance of 3 m. The magnitude of the frictional force is :