A racing car accelerates on a straight road from rest to a speed of 50 m/s in 25 s. Assuming uniform acceleration of the car throughout, the distance covered in this time will be

We are given the initial velocity (u = 0 m/s, since it starts from rest), final velocity (v = 50 m/s), and time (t = 25 s). Assuming uniform acceleration (a), we can use the kinematic equations. First, find the acceleration using v = u + at: 50 = 0 + a 25, which gives a = 50/25 = 2 m/s². Then, find the distance (s) using s = ut + (1/2)at²: s = (0 25) + (1/2) 2 (25)² = 0 + 1 625 = 625 m. Alternatively, the average velocity is (u+v)/2 = (0+50)/2 = 25 m/s. Distance = Average velocity time = 25 m/s 25 s = 625 m.