- Use the relationship Distance = Speed × Time (or Time = Distance / Speed). - Express the time taken in each case relative to the scheduled time, converting all time units to be consistent (e.g., hours). - Set up a system of equations and solve for the unknown distance. - Alternatively, calculate the difference in time taken for the two speeds and use it to find the distance. The total time difference is the sum of the minutes late and minutes early (9 + 6 = 15 minutes). (D/7) - (D/8) = 15/60 = 1/4 hours. This gives D/56 = 1/4, leading to D = 14 km.
If Ramesh walks at 7 kmph, he reaches school 9 minutes late. But if he walks at 8 kmph, he reaches school 6 minutes early. How far is the school ?
Asked in GPSC Prelims CSP 1 2017 · Topic: Mechanics (Newton's Laws of Motion and their applications)
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