For 'n' equal resistors each of resistance 'R' connected in parallel, the total resistance is $R_{total} = R/n$. In this case, n=3, so $R_{total} = R/3$. nected in series and the combi- nation is connected in parallel with a resistance of 36.0 Ω. The equivalent resistance of the combination of three resistors is A. 24.0 Ω B. 12.0 Ω C. 9.0 Ω D. 6.0 Ω Ans: C First, calculate the equivalent resistance of the two resistors connected in series. For resistors in series, the equivalent resistance (R_series) is the sum of individual resistances: R_series = R₁ + R₂ bination (with R_series = 12.0 Ω) is connected in parallel with a third resistance (R₃ = 36.0 Ω). For resistors in parallel, the reciprocal of the equivalent resistance (R_eq) is the sum of the reciprocals of the individual resistances: 1/R_eq = 1/ add the fractions, find a common denominator, which is 36. 1/R_eq = (3/36) + (1/36) = 4/36 1/ R_eq = 1/9 R_eq = 9.0 Ω.